FirstNonRepeatingLetter solution

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Leonid
2025-04-15 11:01:48 +03:00
parent acb617b460
commit ad0acd060a

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package com.algos.codewars;
//Write a function named first_non_repeating_letter† that takes a string input,
// and returns the first character that is not repeated anywhere in the string.
//
// For example, if given the input 'stress', the function should return 't',
// since the letter t only occurs once in the string, and occurs first in the string.
//
// As an added challenge, upper- and lowercase letters are considered the same character,
// but the function should return the correct case for the initial letter. For example, the input 'sTreSS' should return 'T'.
//
// If a string contains all repeating characters, it should return an empty string ("");
//
// † Note: the function is called firstNonRepeatingLetter for historical reasons,
// but your function should handle any Unicode character.
import java.util.LinkedHashMap;
import java.util.Map;
public class FirstNonRepeatingLetter {
public static void main(String[] args) {
System.out.println(firstNonRepeatingLetter("manOn-aMoon"));
}
public static String firstNonRepeatingLetter(String s) {
if (s == null || s.isEmpty()) {
return "";
}
Map<Character, Integer> charCount = new LinkedHashMap<>();
for (int i = 0; i < s.length(); i++) {
char c = Character.toLowerCase(s.charAt(i));
charCount.merge(c, 1, Integer::sum);
}
for (int i = 0; i < s.length(); i++) {
char currentChar = s.charAt(i);
if (charCount.get(Character.toLowerCase(currentChar)) == 1) {
return String.valueOf(currentChar);
}
}
return "";
// List<String> c = s.toLowerCase().chars().mapToObj(ch -> (char) ch).map(String::valueOf).toList();
// for (int i = 0; i < s.length(); i++) {
// if (Collections.frequency(c, c.get(i).toLowerCase()) == 1) {
// return String.valueOf(s.charAt(i));
// }
// }
// return "";
}
}