From 2f2eacbcef5da3f0e8b85067ce025988135c121a Mon Sep 17 00:00:00 2001 From: Leonid Date: Sun, 2 Mar 2025 19:43:10 +0300 Subject: [PATCH] =?UTF-8?q?-=20=D0=A0=D0=B5=D0=B0=D0=BB=D0=B8=D0=B7=D0=BE?= =?UTF-8?q?=D0=B2=D0=B0=D0=BB=20=D0=B4=D0=BE=D1=80=D0=B0=D0=B1=D0=BE=D1=82?= =?UTF-8?q?=D0=BA=D0=B8,=20=D1=83=D0=BC=D0=B5=D0=BD=D1=8C=D1=88=D0=B0?= =?UTF-8?q?=D1=8E=D1=89=D0=B8=D0=B5=20=D0=BA=D0=BE=D0=BB=D0=B8=D1=87=D0=B5?= =?UTF-8?q?=D1=81=D1=82=D0=B2=D0=BE=20=D1=81=D1=81=D1=8B=D0=BB=D0=BE=D0=BA?= =?UTF-8?q?=20=D0=B2=20=D0=BF=D0=B0=D0=B3=D0=B8=D0=BD=D0=B0=D1=82=D0=BE?= =?UTF-8?q?=D1=80=D0=B5.?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit Часто возникает ситуация, когда при разбиении контента на страницы, мы получаем большое количество страниц и ссылки на эти страницы также требуют много места. В такой ситуации стоит сократить вывод ссылок в пагинаторе. https://www.youtube.com/watch?v=Sc3EQBy0tuk&list=PLU2ftbIeotGpAYRP9Iv2KLIwK36-o_qYk&index=28 --- src/main/resources/templates/parts/pager.ftl | 58 +++++++++++++++----- 1 file changed, 44 insertions(+), 14 deletions(-) diff --git a/src/main/resources/templates/parts/pager.ftl b/src/main/resources/templates/parts/pager.ftl index f8317d7..fbfbb8b 100644 --- a/src/main/resources/templates/parts/pager.ftl +++ b/src/main/resources/templates/parts/pager.ftl @@ -1,24 +1,54 @@ <#macro pager url page> + <#if page.getTotalPages() gt 7> + <#assign + totalPages = page.getTotalPages() + pageNumber = page.getNumber() + 1 + + head = (pageNumber > 4)?then([1, -1], [1, 2, 3]) + tail = (pageNumber < totalPages - 3)?then([-1, totalPages], [totalPages - 2, totalPages - 1, totalPages]) + bodyBefore = (pageNumber > 4 && pageNumber < totalPages - 1)?then([pageNumber - 2, pageNumber - 1], []) + bodyAfter = (pageNumber > 2 && pageNumber < totalPages - 3)?then([pageNumber + 1, pageNumber + 2], []) + + body = head + bodyBefore + (pageNumber > 3 && pageNumber < totalPages - 2)?then([pageNumber], []) + bodyAfter + tail + > + <#else> + <#assign body = 1..page.getTotalPages()> +
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